I have been struggling with some issues trying to figure the best safe af ratio by volume, and the numbers are not right to what most are seeing in the real world. It looks like if we have a dual nozzle alky kit this is what I have come up with.
As an example we have an Alky kit running a single m10 nozzle, and a m15 nozzle. The system pressure is 140 psi at WOT.
M10= 10gph@100 psi
M10 new flow rate @140psi= square root (140/100)=1.18 x 10gph=11.8 gph
M15 new flow rate@140psi= 1.18 x15 gph=17.7 gph
Give us a total of 29.5 gph however 1 gal methanol weighs 6.63 lbs
So 29.5 x 6.63=196 lbs/hr you will be injecting in the motor.
At almost 200/lbs that is a lot of alky by volume to fuel.
Lets say we were running 95 lb injectors at 70% duty cycle
95 x 6 injectots=540 lbs x 70%=378 lbs hr
This means that on a ratio scale we have 196lb/378lb x100=52% alky to fuel ratio does this not seem off?
That means we would need an equivalent af ratio shown on your wideband using the gas scale as
new af= (meth% * meth stoich)+(1-meth%)*stoichGAS)
new af=( .52*6.4)+(1-.52)*14.7
=(3.328+7.056)
=10.38
Which means to run 10.38 would mean the same as running at 14.7
This seems way off. I need the experts to chime in please!
As an example we have an Alky kit running a single m10 nozzle, and a m15 nozzle. The system pressure is 140 psi at WOT.
M10= 10gph@100 psi
M10 new flow rate @140psi= square root (140/100)=1.18 x 10gph=11.8 gph
M15 new flow rate@140psi= 1.18 x15 gph=17.7 gph
Give us a total of 29.5 gph however 1 gal methanol weighs 6.63 lbs
So 29.5 x 6.63=196 lbs/hr you will be injecting in the motor.
At almost 200/lbs that is a lot of alky by volume to fuel.
Lets say we were running 95 lb injectors at 70% duty cycle
95 x 6 injectots=540 lbs x 70%=378 lbs hr
This means that on a ratio scale we have 196lb/378lb x100=52% alky to fuel ratio does this not seem off?
That means we would need an equivalent af ratio shown on your wideband using the gas scale as
new af= (meth% * meth stoich)+(1-meth%)*stoichGAS)
new af=( .52*6.4)+(1-.52)*14.7
=(3.328+7.056)
=10.38
Which means to run 10.38 would mean the same as running at 14.7
This seems way off. I need the experts to chime in please!