I have always wanted to ask this question - with relation to this subject.
In a hypothetical situation, if a crankshaft is cut 0.010" say on the mains - to achieve an ultimate oil clearance of 0.002" - this would be 2.500" - 0.010" = 2.490" for the crankshaft main journal OD.
What would the needed dimension be for the ID of the journal bore w/ bearing intact need to measure for this 0.002" oil clearance dimension?
Would the ID need to be:
Option A ---> 2.490" + 0.002" = 2.492" - this gives 0.001" above & below the journal.
Option B ---> 2.490" + (0.002" * 2) = 2.494" - this gives 0.002" above & below the journal.
I know that it is done the other way around, where the line bore/hone is conducted 1st, the bearings are installed in the cradels & measurements are taken here - and then the crankshaft is cut accordingly, yet, is the difference between the dimensions of the Crankshaft OD & it's corresponding housing w/ bearing 2/1000" or 4/1000" ?
Just curious.
TIA