Two bar at 0 psi is about 2.3 volts.
Two bar at 15 psi is about 4.85 volts.
y=mx+b
2.3=0m+b
b=2.3
m=(y1-y0)/(x1-x0)=(4.85-2.3)/(15-0)=0.17
x=0psi, y=(0*0.17)+2.3=2.3
x=1psi, y=(1*0.17)+2.3=2.47v
x=2psi, y=(2*0.17)+2.3=2.64v
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x=15psi, y=(15*0.17)+2.3=4.85v (checks)