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SignUp Now!Scott, the secrets out of the box. It's time for the nitrous revolution.
Don't let the 'man' keep you down.
Anything that God made available to us on this green earth is fair game in my book.
Huh?
I predict an increase in the demand for headgaskets over the next few months....Time to buy stock in Fel-Pro:tongue:
Don
Since Methanol has about 10% more specific energy than Gasoline, I would say that your 190 shot is more like a 209 hp shot.
Now the question that I'm dying to know the answer to.
Let's take a compressor that is operating at a pressure ratio of 2 to one. The air entering the turbo has the normal content of oxygen that is in the air all around us. The oxygen content is twice as much per cylinder volume after the compressor. Keeping the math simple and not taking into consideration the temperature rise. Is this correct? If so, then if we start with an air mix that has a higher percentage of oxygen in it and run it through the compressor, have we still doubled the oxygen content per cylinder volume? Keeping heat out of the equation for now. I am in desperate need of some math wizards on this one.
Very good point.I may be in over my head on this one but I think if you are starting off with a infinite amount of that air with more oxygen in it then you would certainly be doubling its density after the compressor regardless.
But, if I am to guess where you are going with this, if you inject nitrous pre turbo then the amount of oxygen vs volume is going to increase. As engine rpm increases, so does volume of "air" processed but since the volume of nitrous is a constant your're going to have an ever changing oxygen content vs volume of "air" pre turbo and therefore post turbo. The nitrous volume would have to have some sort of ramp to accurately predict the amount of oxygen actually entering the engine to keep it constant.