87we410877
Well-Known Member
- Joined
- Apr 5, 2005
- Messages
- 2,634
Gasoline burns completely at 14.7:1 a/f ratio and Methanol burns at a ratio of 6.45:1 a/f ratio I think?? For comparison sake, if you remove 1lb/hr of fuel, you would replace it with 2lb/hr of Methanol. Basically because methanol makes the power at a far richer a/f ratio, you have to take that into consideration when you spray it, especially in large quantities.You have to nearly double the quantity of meth compared to the amount of fuel you remove, hence the increased a/f ratio. Difficult for me to explain what I mean! sorry
I understand. Just how exactly with a bank to bank would you pull fuel? Would you just lower the air fuel by the vloumetric efficiency table the normal way and then add alcohol untill the actual a/f comes back up? Thanks alot. I have to do alot of reading on the fast help section.